C++ help about looping.my program also involves arrays?

Hi, below is my c++ program this program is suppose to give the denomination of a given amount.





for example if the amount entered is 3897.69


the output should be like this:


1000 * 3 = 3000


500 * 1 = 500


200 * 1 = 200


100 * 1 = 100


50 * 1 = 50


and so on..


my problem evolves on the looping thing and the output. can you help me?





#include %26lt;iostream.h%26gt;


main()


{


int cntr;


int ans[14];


int value;


float d[14]={1000,500,200,100,50,20,10,5,1,0.5...


cout%26lt;%26lt;endl%26lt;%26lt;" Enter value: ";


cin %26gt;%26gt; value;


{


ans[cntr]=value/d[cntr];


value=value-d[cntr]*ans[cntr];


while(cntr%26gt;15)


{


cntr=cntr+1;


ans[cntr]=value/d[cntr];


}


cout%26lt;%26lt;" "%26lt;%26lt;d[cntr]%26lt;%26lt;" * "%26lt;%26lt;ans[cntr]%26lt;%26lt;" = "%26lt;%26lt;d[cntr]*ans[cntr]%26lt;%26lt;endl;


}


}








thanks in advance!

C++ help about looping.my program also involves arrays?
You're on the right track. The easiest way to do things such as this is by using the mod operator (%). The mod operator essentially returns the remainder of division by the second operand. For instance, take your value of 3897.69. Start at the biggest denomination of 1000.





total = 3897.69


remainder = total % 1000 = 897.69


then the number of thousands is floor(3897.69 / 1000)


total = remainder





You then just need to loop over that with each denomination and save the number of each denomination in a separate array. Do you understand how to generalize this now?
Reply:i don't know the script but i can help u with my logic


1. u must know how long number entered


2. count it and loop it


3. for first number multiply it with 1 join string zero (long number entered) - 1 and then convert it to decimal


example if 1 entered 1000 - %26gt; length = 4


so 1 * 1 000 ( 4 -1)


4. and take the number in the second row multiply with 1 join string zero (long number entered) - 2 and then convert it to decimal


5. and so on
Reply:just use





value=value%d[cntr];





instead of "value=value-d[cntr]*ans[cntr];"





can U wait a while I'hv to see prgramm carefully and then solve UR problem